In the equation:

(2n^3)^4 (n^-2)^-1

I work it and get 16n^12-n^2. I am not sure what to do with the "-n^2". Help woulld be greatly appreciated.

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- November 7th 2010, 12:13 PMmrkingEquations with variables and exponents
In the equation:

(2n^3)^4 (n^-2)^-1

I work it and get 16n^12-n^2. I am not sure what to do with the "-n^2". Help woulld be greatly appreciated. - November 7th 2010, 01:00 PMpickslides

Can you finish it from here using simple index laws?

__Spoiler__: - November 7th 2010, 01:05 PMHallsofIvy
First, although it may seem "picky", you don't have an equation here, you have an expression. (It isn't

**equal**to anything.)

What do you**want**to do with the ? That is, what are you trying to do with the original expression? Simplify it? seems simple enough to me! You could, if you wanted, factor out an " ". so [tex]16n^{12}- n^2= n^2(16n^{10}- 1). If you really wanted to you could factor that further- is the difference of two squares and can be factored as . whether is "simpler" than is a matter of taste or, perhaps better, of what you wanted to do with it from here. - November 7th 2010, 01:11 PMpickslides
- November 7th 2010, 01:30 PMHallsofIvy
I'm going to slide right out of that one!

- November 7th 2010, 01:52 PMWilmer
Hmmm....I get a simple 16n^14 ; where does the - come from?

- November 7th 2010, 01:54 PMpickslides
- November 7th 2010, 04:56 PMWilmer
- November 7th 2010, 04:58 PMpickslides
Its an expression, thanks smarty pants!