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Math Help - Quick Question! Solving eq with Pwer (eg. ^5)

  1. #1
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    Quick Question! Solving eq with Pwer (eg. ^5)

    There is this question I have been trying to get my head around, and cant seem to get it! Its trying to find 'G':

    19x=9x(1+G)^5


    So I do,

    18/9=(1+G)^5
    2=(1+g)^5

    But I am completely lost as to what to do next because of the power sign. I have tried to read the stick posts but not being a numerical person, they just confuse me more.

    any pointers?
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  2. #2
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    Oh sorry and I should have said the answer is g=14.87

    But I just dont know how to get their!

    Thanks folks
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  3. #3
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    Quote Originally Posted by bamboozled View Post
    There is this question I have been trying to get my head around, and cant seem to get it! Its trying to find 'G':

    19x=9x(1+G)^5


    So I do,

    18/9=(1+G)^5
    2=(1+g)^5

    But I am completely lost as to what to do next because of the power sign. I have tried to read the stick posts but not being a numerical person, they just confuse me more.

    any pointers?
    Is it meant to be 19 or 18?

    The first step in solving 2 = (1 + g)^5 is to take the fifth root of both sides: 2^(1/5) = 1 + g.
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  4. #4
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    Quote Originally Posted by mr fantastic View Post
    Is it meant to be 19 or 18?

    The first step in solving 2 = (1 + g)^5 is to take the fifth root of both sides: 2^(1/5) = 1 + g.
    Thanks for your replt mr fantastic sorry, its meant to be 19.

    Thank you so much! Despite my error, you still managed to help solve it.

    Thank you!!!!!!!!
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