y = 2^[(x^2) - 2x]
I need solution!!
Thanks in advance
The question is: What is the minimum value of the function f(x) = 2^[(x^2) - 2x] ?
We have to complete the square and then find the minimum value for y.
im stuck here:
y = 2 ^ [ ((x-1)^2) -1 ] , now how can i get rid of the 2?
the answer is 2^(-1), i want the solution
sry about all the brackets
So the question I asked you is what when we find the minimum value of
why does this make
Completing the square gives
The minimum value occurs when the term
This gives the smallest value of the quadratic as
So the minimum function value is