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Math Help - Express y in terms of x for the relation?:

  1. #1
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    Express y in terms of x for the relation?:

    4x^2 - 4xy + y^2 - 2x + y - 6 = 0

    First can someone tell me what I'm supposed to actually do?
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  2. #2
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    Isolate the y variable. That is, rearrange that equation in the form of

    y = [expressions in terms of x, with no y terms].
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  3. #3
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    Quote Originally Posted by Sorena View Post
    4x^2 - 4xy + y^2 - 2x + y - 6 = 0
    there are two solutions for y in terms of x ...

    4x^2 - 4xy + y^2 - 2x + y - 6 = 0

    (4x^2 - 4xy + y^2) - (2x - y) - 6 = 0

    (2x - y)^2 - (2x - y) - 6 = 0

    [(2x-y) - 3][(2x-y) + 2] = 0

    2x - y = 3 ... y = 2x-3

    2x - y = -2 ... y = 2x+2
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