Express y in terms of x for the relation?:

**Sorena** · November 3rd 2010, 04:58 PM

4x^2 - 4xy + y^2 - 2x + y - 6 = 0

First can someone tell me what I'm supposed to actually do?

**Gusbob** · November 3rd 2010, 05:12 PM

Isolate the y variable. That is, rearrange that equation in the form of

y = [expressions in terms of x, with no y terms].

**skeeter** · November 3rd 2010, 05:20 PM

Originally Posted by Sorena

4x^2 - 4xy + y^2 - 2x + y - 6 = 0

there are two solutions for y in terms of x ...

$4x^2 - 4xy + y^2 - 2x + y - 6 = 0$

$(4x^2 - 4xy + y^2) - (2x - y) - 6 = 0$

$(2x - y)^2 - (2x - y) - 6 = 0$

$[(2x-y) - 3][(2x-y) + 2] = 0$

$2x - y = 3$ ... $y = 2x-3$

$2x - y = -2$ ... $y = 2x+2$

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