Is the following true, and if so, how do you prove it?

$\displaystyle \sqrt[n]{x_1x_2x_3...x_n} \ge \sqrt[n]{(x_1+1998)(x_2+1998)...(x_n+1998)} - 1998$

Edit: Sorry never mind, this is false

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- Oct 31st 2010, 07:41 AMoleholehDifficult inequality
Is the following true, and if so, how do you prove it?

$\displaystyle \sqrt[n]{x_1x_2x_3...x_n} \ge \sqrt[n]{(x_1+1998)(x_2+1998)...(x_n+1998)} - 1998$

Edit: Sorry never mind, this is false