# How does the logs in the equation below cancel out?

• Oct 31st 2010, 06:02 AM
CSG18
How does the logs in the equation below cancel out?
Find x:

log 5 = log x

Preferably without making it equal 0 please.
• Oct 31st 2010, 06:10 AM
earboth
Quote:

Originally Posted by CSG18
Find x:

log 5 = log x

Preferably without making it equal 0 please.

Use the logarithms as exponents to the base of the logs:

$b^{\log_b(a)}=a$