I know I shoudl know this, but it's late and for some reason I am drawing a blank. Any help would be appreciated. Thanks
How does $\displaystyle \frac{\frac{3}{x}}{1+\frac{4}{x^2}}$ simplify to $\displaystyle \frac{3x}{x^2+4}$
I know I shoudl know this, but it's late and for some reason I am drawing a blank. Any help would be appreciated. Thanks
How does $\displaystyle \frac{\frac{3}{x}}{1+\frac{4}{x^2}}$ simplify to $\displaystyle \frac{3x}{x^2+4}$
Hello, dbakeg00!
$\displaystyle \text{How does }\,\dfrac{\frac{3}{x}}{1+\frac{4}{x^2}}\,\text{ simplify to }\,\dfrac{3x}{x^2+4}$
Multiply by $\displaystyle \dfrac{x^2}{x^2}$
. . $\displaystyle \displaystyle \frac{x^2}{x^2}\cdot \frac{\frac{3}{x}}{1+\frac{4}{x^2}} \;=\;
\dfrac{x^2\left(\frac{3}{x}\right)}{x^2\left(1 + \frac{4}{x^2}\right)} \;=\;\frac{3x}{x^2+4} $