i am wanting to rearrange to make h the subject h the subject and then b the subject

S= √(b2-h2)

can someone please help me

steve

Printable View

- Oct 30th 2010, 01:43 PMsugst893help rearranging this
i am wanting to rearrange to make h the subject h the subject and then b the subject

S= √(b2-h2)

can someone please help me

steve - Oct 30th 2010, 01:50 PMpickslides
Is your equation $\displaystyle S = \sqrt{b^2-h^2}$ ?

If so start by squaring both sides,

$\displaystyle S = \sqrt{b^2-h^2}$

$\displaystyle S^2 = b^2-h^2$

Then adding $\displaystyle h^2$ to both sides

$\displaystyle S^2+h^2 = b^2$

Finally taking the square root of both sides.

$\displaystyle \sqrt{S^2+h^2} = b$

$\displaystyle b = \sqrt{S^2+h^2} $

Do you follow?(Nod) - Oct 30th 2010, 01:50 PMmr fantastic
- Oct 30th 2010, 02:19 PMsugst893
- Oct 30th 2010, 06:16 PMmr fantastic
- Oct 31st 2010, 11:10 AMsugst893
ok so

first i would square both sides

then subtract s^2 from both sides

giving me h=sqrt{S^2-b^2}

stephen - Oct 31st 2010, 11:22 AMUnknown008
No, if you want to make it this way, it's a little different.

$\displaystyle S = \sqrt{b^2-h^2}$

Square both sides:

$\displaystyle S^2 = b^2-h^2$

Now, Move b^2;

$\displaystyle S^2 - b^2 = -h^2$

You see that there is a minus sign? Multiply both sides by -1:

$\displaystyle -S^2 + b^2 = h^2$

Rearrange:

$\displaystyle b^2 - S^2= h^2$

Now, you take the square root.

$\displaystyle \sqrt{b^2 - S^2}= h$

$\displaystyle h = \sqrt{b^2 - S^2}$