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Math Help - Factoring Complex Trinomial Quadratics

  1. #1
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    Factoring Complex Trinomial Quadratics

    - 20x-24x+32
    GCF: 4
    4(-5x-6x+8)

    4(-5x-10)(-5x+4) / 4

    Product of AC= -40
    Sum of B= -6

    Please help i cant divide -5x by 4, even if i split 4 to 2x2
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by buck View Post
    - 20x-24x+32
    GCF: 4
    4(-5x-6x+8)

    4(-5x-10)(-5x+4) / 4

    Product of AC= -40
    Sum of B= -6

    Please help i cant divide -5x by 4, even if i split 4 to 2x2
    where is /4 coming from?? how can you just divide by 4 like that?!

    factor out -4, you get \displaystyle -4(5x^2 + 6x - 8)

    you're using the ac method, so i will as well. here ac = -40 and b = 6, so think of two number that when you multiply them you get -40, but you add them and get 6. 10 and -4 works. so split the middle term into those two, you have:

    \displaystyle -4(5x^2 + 10x - 4x - 8)

    now factor what's inside the brackets using "factor by grouping"
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  3. #3
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    wait can i divide it by -20 because my teacher told me you are supposed to divide it by A
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