Solve each of the following eq.
1. 2 log(base 2)(x + 2) = log(base2)(x + 14)
2. log(base 27)(x) = log(base x)(27)
How to start?
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Remember that you can remove the bases once there are only logs. So, raise the power
For the other one, change the base.
EDIT: I didn't notice the '2'. Changed it now.
In other words - solve the quadratic but remember that x must be greater than -2
For number 2 use the change of base rule
Solve using the difference of two squares. Again, from the domain,
After 1/log(base x)(27) =log(base x)(27)
Then,I'm kinda confused.....Is this the correct way?
Yes that is correct.
Now bring the x's to one side giving us:
Can you carry on from there?
(Remember gives 2 answers)
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