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Math Help - i'm stuck on this problem

  1. #1
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    Unhappy i'm stuck on this problem

    the difference of two numbers is 33. the second is 7 l ess than 3times the first what are the numbers?
    i thought 3x-7 = 33 i'm stuck to solve this please help me thanks
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  2. #2
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    I think the two numbers should be 77 and 44 because 77-44=33 and 77 multiplied 3=231/7=33. I hope it's right
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  3. #3
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    Quote Originally Posted by lizard4 View Post
    the difference of two numbers is 33. the second is 7 l ess than 3times the first what are the numbers?
    i thought 3x-7 = 33 i'm stuck to solve this please help me thanks
    Let the numbers be x and y, then

    x-y=33

    and

    y=3x-7

    substitute the second into the first to get:

    -2x+7=33

    so x=-13, and then y=-46.

    But if we instead have as the first equation y-x=33, then on substitution
    we have:

    2x-7=33,

    so x=20, and y=53.

    RonL
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  4. #4
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    Quote Originally Posted by lizard4 View Post
    the difference of two numbers is 33. the second is 7 l ess than 3times the first what are the numbers?
    i thought 3x-7 = 33 i'm stuck to solve this please help me thanks
    You have seen the solution to a number of these types of problems in recent days. If you are still having problems, it might be a good idea to tell us where those problems are. It would be better than having us give you solutions that (apparently) aren't helping you.

    -Dan
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