How can I solve for r in the equation 2x = x^r for 0<x<1? I did the following: log 2 + log x = r log x r = log 2 / log x + 1 However, for the value of x = .5, r evaluates to 0, which gives you the equation 2x = 1.
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Originally Posted by adnaps1 How can I solve for r in the equation 2x = x^r for 0<x<1? I did the following: log 2 + log x = r log x r = log 2 / log x + 1 However, for the value of x = .5, r evaluates to 0, which gives you the equation 2x = 1. what is wrong with ? is the variable that has the restriction. ... invalid solution since since ...
Thanks a lot, skeeter.