A mountain climber is scaling a 300 foot cliff at a constant rate. The climber starts at the bottom at 12:00 P.M. By 12:30 P.M., the climber has moved 62 feet up the cliff.

Write an equation that gives the distace d (in feet) remaining in the climb in terms of the time t (in hours). What is the slope of the line?

MY WORK:

The points are (0,0) and (1/2,62).

The point (0,0) represents the location at the bottom of the mountain where the climber starts to climb.

Is this right so far?

I want to write an equation in the form y = mx + b, where m = slope and b = y-intercept.

m = (62 - 0)/(1/2 - 0)

m = 62 divided by 1/2

m = 124

The slope is 124.

Replace y with d.

I gotd = 124t + 300

Is this correct? If not, can someone answer this question?