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  1. #1
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    Smile algebra help

    a small firm produces both am and am/fm car radios. the am radios take 15h to produce and the am/fm radios take 20h..the number of production hours is limited to 300h per week. The plant's capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 am radios and at least 3am/fm radios be produced per week. write a system of inequalities representing this situation. Then draw a graph of the feasible region given this condition in which x is the number of am radios and y is the number of am/fm radios
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  2. #2
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    Quote Originally Posted by lizard4 View Post
    a small firm produces both am and am/fm car radios. the am radios take 15h to produce and the am/fm radios take 20h..the number of production hours is limited to 300h per week. The plant's capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 am radios and at least 3am/fm radios be produced per week. write a system of inequalities representing this situation. Then draw a graph of the feasible region given this condition in which x is the number of am radios and y is the number of am/fm radios
    Hello,

    let x be the amount of am radios;
    let y be the amount of am/fm radios

    Then you get the following system of inequaltities:

    x+y\leq 18 \Longrightarrow y \leq -x+18
    x\geq 4
    y \geq 3
    15x + 20y \leq 300 \Longrightarrow y \leq -\frac{3}{4}x + 15

    I've attached a diagram of the graph
    Attached Thumbnails Attached Thumbnails algebra help-linop_radios.gif  
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