F weight is 140% of I’s weight. R’s weight is 90% of M’s weight. M’s weight is twice as much as I’s. What percentage of F’s weight is R’s weight?
I’ve done like this:
Let, x be the weight of I.
So, F = 1.4x
M = 2x
R = 0.9 (2x)
Therefore required percentage:
Is this right?
Another one:
A committee consists of 9 men & 4 women. In how many ways can a sub-committee of 3 men & 1 women be chosen?
So far I think,
Choosing 3 men from 9 men & 1 woman from 4 women.
So, the number of ways =
Is that right?