Any non-integer solutions should be given as fractions in their simplest form.

5a-b=9
a+6b=-3

2. Start by multiplying the first equation by 6. Then add the two equations together to eliminate $b$.

3. hi,
what's next?

4. Why not show what you have done and where you are stuck?

5. I multiplied the first equation by 6
and added the 2 equations together

30a - b = 54
a+6b = -3

31 + b =51

6. It should actually have been

$30a - 6b = 54$

$a + 6b = -3$.

Now try adding the equations together. What do you get?

7. Is it

31a+12b=51?

Thanks