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quadratic equations
hi, i need to make this into a quadrattic equation but there is a pert on the table which i can't remember what to do!
when you have x then -3,-2,-1,0,1,2,3
under that you puy Y and i can remember how to work that out! if you can help i will be very thankful!
my question is Y= x^2-4x+1 by the way
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Replace the values of x in the equation given to you!
For example, under -3, you put:
^2 - 4(-3) + 1 = 9 + 12 + 1 = 22)
Hence:

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thanks for answering my question! under -2 it would be 11?
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^2 - 4(-2) + 1 = 4 + 8 + 1)
Does this equal 11?
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no its 13, i think i got it now!! would -1=3?
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Quote:
Originally Posted by
andyboy179
would -1=3?
I get 6
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Think of it again:
^2 - 4(-1) + 1 = 1 + 4 + 1)
Does this make 1?
remember that when you multiply two negative numbers, they become a positive number.
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would 0 =1
1=0
2=1
3=1???
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for 0: yes.
For 1: ^2 - 4(1) + 1 = 1 - 4 + 1)
For 2: ^2 - 4(2) + 1 = 4 - 8 + 1)
For 3: ^2 - 4(3) + 1 = 9 - 12 + 1)
Hm.. you need to work your basic calculations more...
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actually would this be it:
-3=19
-2=11
-1=5
0=1
1=-1
2=-1
3=1
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Are you sure you posted the right equation?
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cr@p, no i didn't its -4X sorry!!!!!!!!
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I still have no idea what the equation actually is... (Speechless)