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Math Help - setting up equations

  1. #1
    Newbie
    Joined
    Oct 2010
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    setting up equations

    If anyone can help me with this problem, that would be great. Thanks in advance.

    I can't seem to set up this problem correctly.

    Twice as many dimes as quarters
    3 times as many nickles as quarters
    how many dimes are there?
    Total of 54 coins


    This is what I came up with

    Q+N+D=54
    2d=Q
    3n=Q
    Q+3n+2d=54?
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  2. #2
    MHF Contributor Unknown008's Avatar
    Joined
    May 2010
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    Mauritius
    Posts
    1,260
    It's the other way round. Think of it this way.

    D is bigger than Q. You need to multiply Q by 2 to get the equal amount of D.

    So,

    D = 2Q

    Similarly,

    N = 3Q

    And

    Q + N + D = 54

    From there, put everything in Q.

    Q + 3Q + 2Q = 54

    Solve for Q. The rest will come easily.


    Think in terms of "what should I do to X to make it equal to Y?"
    It helped me a lot, maybe it can hel you too!
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