$\displaystyle \left (\frac{\pi-3 }{2} \right )^{x^2-x}+\frac{6\pi}{4}-\frac{\pi^{2}+9}{4}> 0$

What I could do:confused:

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- Oct 20th 2010, 10:52 AMLilInequality
$\displaystyle \left (\frac{\pi-3 }{2} \right )^{x^2-x}+\frac{6\pi}{4}-\frac{\pi^{2}+9}{4}> 0$

What I could do:confused: - Oct 20th 2010, 10:55 AMAckbeet
I would throw everything over to the RHS that doesn't have an x in it. What does that give you?

- Oct 20th 2010, 10:59 AMLil
- Oct 20th 2010, 10:59 AMearboth
- Oct 20th 2010, 11:00 AMAckbeet
RHS means "Right Hand Side". Similarly, LHS means "Left Hand Side".

- Oct 20th 2010, 11:00 AMLil
- Oct 20th 2010, 11:02 AMAckbeetQuote:

$\displaystyle \displaystyle\left (\dfrac{\pi-3 }{2} \right )^{x^2-x}>\dfrac{6\pi}{4}-\dfrac{\pi^{2}+9}{4}$

Quote:

$\displaystyle \displaystyle\left (\dfrac{\pi-3 }{2} \right )^{x^2-x}>\dfrac{\pi^{2}+9}{4}-\dfrac{6\pi}{4}$

- Oct 20th 2010, 11:05 AMLil