I don't think your equations are wrong. 'How did you solve them?' is the question on my mind.
Because the solutions don't seem to work.
This problem, is seriously bugging me:
A collection of nickels, dimes, and quarters consists of 12 coins with a total value of $1.45. If the number of nickels is 2 less than the number of dimes, how many of each coin are contained in the collection?
I thought, I had it right the first time, but my totals didn't add up to 1.45. I don't understand what I am doing wrong.
The three equations I came up with are:
x + y + z = 12
x = y - 2 or x - y = -2
5x + 10y + 25z = 145
Are my equations wrong?
x + y + z = 12
z - y = -2
5x + 10y + 25z = 145
x + y + z = 12
x - y = -2
2x + z = 10
x + y + z = 12
5x + 10y + 25z = 145
10x + 10y + 10z = 120
5x + 10y + 25z = 145
5x - 15z = -25
2x + z = 10
5z - 15z = -25
30x + 15z = 150
5x - 15z = -25
35x = 125
x = NOT RIGHT!
Well originally I had 4 here, but while typing it out, I see that I subtracted and also had 125 instead of 150 on the last step to get 25x = 100, but it should have been addition...and now it's alllllllllll messed up again. Does anyone see an error in my math?
I even went as far as trying to say that if x = 1 - 12, and y being two more...and not any of those answers were correct. Is something wrong with this problem or me!!! LOL!!!
I keep coming up with this...
x =
y=
z=
And if this is right I am going to uppercut my teacher...