# Thread: Solve for x & y

1. ## Solve for x & y

(3 + j2)(-6 + j)=(x + jy)(-2 + j4)

2. Originally Posted by neoza

(3 + j2)(-6 + j)=(x + jy)(-2 + j4)
$
(3+2\bold{j})(-6+\bold{j})=-18-2 -12\bold{j} +3\bold{j} = -20-9\bold{j}
$

and (assuming $x$ and $y$ are real:

$
(x + y\bold{j})(-2 + 4\bold{j})=-2x-4y -2y \bold{j} +4x \bold{j}=-2(x+2y)+2(2x-y)\bold{j}
$

Now equate real and imaginary parts to get:

$
x-2y=10
$

and:

$
4x-2y=-9
$

and now solve the simultaneous equations.

RonL