I have been given the density of milk = $\displaystyle 990 kg m^{-3} $

and a volume of $\displaystyle 3000 Litres h^{-1} $ I need to work out the

mass.

I know $\displaystyle \rho\\\\\\\\\\\\( kg m^{-3} ) = \frac{m( kg)}{ v( m^{3})} $

so I need to convert $\displaystyle 3000 Litres h^{-1} $ to meters,

can some please check my working.

1L = 1000 ml

1 ml = 1cm

1m = 100cm

$\displaystyle \frac{3000 L}{1 h } \times \frac{1000ml}{1L} = \frac{3000000 ml}{h} = \frac{3000000 cm}{h} $

$\displaystyle \frac{3000000 cm}{h} \times \frac{1m}{100cm} = \frac{30000 m}{h} $

to get m^{3} = $\displaystyle (\frac{30000}{h})^{3} = 2.7 \times 10^{13} m^{3} h^{-1} $

so $\displaystyle m kg = 990 kg m^{-3} \times 2.7 \times 10^{13} m^{3} = 2.673 \times 10^{16} kg $

is this correct ?