... that I forgot how to do. -_- In the equation -dsin35 = -4.9(dcos35/25)^2, is it (d^2 x cos35^35)? or simply (dcos35)^2? thanks in advance
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What?!
Originally Posted by qswdefrg -4.9(dcos35/25)^2, $\displaystyle \displaystyle -4.9\left(\frac{d\cos (35)}{25}\right)^2 = \frac{-4.9d^2\cos^2 (35)}{25^2} = \frac{-4.9d^2\cos (35)\times \cos (35)}{25^2} $
thanks so much! :')
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