# Thread: Sum and Product of the Roots of a Quadratic Equation

1. ## Sum and Product of the Roots of a Quadratic Equation

Studying quadratic equations and i'm at a chapter where it details the sum and product of the roots of a quadratic.

It starts off with the following:

If $\alpha$ and $\beta$ are the roots of the quadratic equation $ax^2+bx+c=0$ then $(x-\alpha)(x-\beta)=0$

Can anyone explain how that equality conclusion is reached?

Quadratic equation - Wikipedia, the free encyclopedia

p.s:

By the way...

ax^2+bx+c=a*(x-\alpha)(x-\beta)

3. Hey thanks for the reply. It doesn't say in that article how you can factor $ax^2+bx+c$ to $(x-\alpha)(x-\beta)=0$. It just says let us assume it factors that way. (under lagrange resolvents)

It would be helpful and appreciated if you could break it down

4. Thanks!