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Math Help - Sum and Product of the Roots of a Quadratic Equation

  1. #1
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    Sum and Product of the Roots of a Quadratic Equation

    Studying quadratic equations and i'm at a chapter where it details the sum and product of the roots of a quadratic.

    It starts off with the following:

    If \alpha and \beta are the roots of the quadratic equation ax^2+bx+c=0 then (x-\alpha)(x-\beta)=0

    Can anyone explain how that equality conclusion is reached?
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  2. #2
    MHF Contributor Also sprach Zarathustra's Avatar
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    Read here:

    Quadratic equation - Wikipedia, the free encyclopedia

    p.s:

    By the way...

    ax^2+bx+c=a*(x-\alpha)(x-\beta)
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  3. #3
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    Hey thanks for the reply. It doesn't say in that article how you can factor ax^2+bx+c to (x-\alpha)(x-\beta)=0. It just says let us assume it factors that way. (under lagrange resolvents)

    It would be helpful and appreciated if you could break it down
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    MHF Contributor Also sprach Zarathustra's Avatar
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  5. #5
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    Thanks!
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