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Math Help - Algebra Help Needed

  1. #1
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    Algebra Help Needed


    Can anyone please show me the simpliest way to work out these ?

    25-7a=27-4a

    11-7(2-a) = 18

    4
    - (x+3) = 6
    5

    Thanks heaps
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by chhoeuk View Post

    Can anyone please show me the simpliest way to work out these ?

    25-7a=27-4a
    we want to solve for a, so our objective is to get a by itself on one side of the equal sign.

    25 - 7a = 27 - 4a .......let's get all a's on the left

    \Rightarrow 25 - 7a + 4a = 27 ........i added 4a to both sides

    \Rightarrow -7a + 4a = 27 - 25 .......i subtracted 25 from both sides

    \Rightarrow -3a = 2 .........i computed both sides

    \Rightarrow a = - \frac {2}{3} ........i divided both sides by -3



    11-7(2-a) = 18
    11 - 7(2 - a) = 18 ........first let's expand the brackets. multiply everything inside by -7

    \Rightarrow 11 - 14 + 7a = 18 ........now clean things up a bit

    \Rightarrow -3 + 7a = 18 ..........now add 3 to both sides

    \Rightarrow 7a = 21 ................now divide both sides by 7

    \Rightarrow a = 3


    4
    - (x+3) = 6
    5


    \frac {4}{5} (x + 3) = 6 ......again, expand the brackets first

    \Rightarrow \frac {4}{5}x + \frac {12}{5} = 6

    can you take it from here? remember, your objective is to get x on one side by itself, anything else on that side, we get rid of it by adding, subtracting or dividing both sided by it
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