Hi, I am struggling to simplify: The dot/mark in front of the 4 is meant to be a multiplication sign. Any help would be great thanks
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Just note that: $\displaystyle (a\cdot b)^c = a^c \cdot b^c$ and that $\displaystyle x^a + x^b = x^{a+b}$ You should be able to figure it our easily now.
Originally Posted by raphw Just note that: $\displaystyle (a\cdot b)^c = a^c \cdot b^c$ and that $\displaystyle x^a + x^b = x^{a+b}$ You should be able to figure it our easily now. I know that $\displaystyle (a^m)^n = a^m^n$ So on first half of equation I get : $\displaystyle 2x^-^(^1^/^4^) ^\cdot ^(^2^)$ Am I heading in the right direction?
Originally Posted by shadowzoe So on first half of equation I get : $\displaystyle 2x^-^(^1^/^4^) ^\cdot ^(^2^)$ Not quite: [2x^(-1/4)]^2 = 2^(1*2)x^(-1/4 * 2) = 4x^(-1/2)
Thanks. So then $\displaystyle 4x^-^1^/^2 \cdot 4x^3^/^2 = (4x)^1$ Thus Answer = 4x Is my thinking correct?
Originally Posted by shadowzoe Thus Answer = 4x You get a ceegar !!
Originally Posted by Wilmer You get a ceegar !! Wilmer, can I be a pain? If X=2 I cannot get the first equation to match 4x ... where am I going wrong?
You simply got the answer wrong. $\displaystyle 4x^-^1^/^2 \cdot 4x^3^/^2 \ne (4x)^1$ but: $\displaystyle 4x^-^1^/^2 \cdot 4x^3^/^2 = (4)^2(x)^1 = 16x$
Thanks Raphw and Wilmer. Yeah I woke up this morning and realised I missed of one of the fours at the end. Thanks again
Originally Posted by raphw Just note that: $\displaystyle (a\cdot b)^c = a^c \cdot b^c$ and that $\displaystyle x^a + x^b = x^{a+b}$ This is incorrect. I presume raphw meant to write $\displaystyle (x^a)(x^b)= x^{a+b}$ with a multiplication on the left side, not a sum. You should be able to figure it our easily now.
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