Hi all;
don't know how to tackle this type of problem.
Carla is 4 times older than her daugther in 30 years she will be half her age how old are they now?
Thanks.
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Hi all;
don't know how to tackle this type of problem.
Carla is 4 times older than her daugther in 30 years she will be half her age how old are they now?
Thanks.
Daughter's present age = x. Daughter's age in 30 years time = x + 30.Quote:
Originally Posted by anthonye
Carla's present age is y. Carla's age in 30 years time is y + 30.
Use the above to form equations from the statements below:
"Carla is 4 times older than her daugther":
"in 30 years she [the daughter] will be half her [Carla] age":
Solve the equations for x and y.
Just don't see it.
You need to make a better effort than that.Quote:
Originally Posted by anthonye
What about the equation corresponding to "Carla is 4 times older than her daughter". Surely you can write the equation (did you even look at my definitions for x and y?)
What about the equation corresponding to
Suppose the daughter's age were 5. How old would Carla be?
Suppose the daughter's age were 10. How old would Carla be?
What did you do? Do the same thing with the x and y mr fantastic used.
Yes been looking at this for a bit just can't see word problem solutions don't know why got to go to work now any help is appreciated
thanks again.
Can someone tell me if carla = 30 and her daughter = 7.5.
Thanks
This is not correct.Quote:
Originally Posted by anthonye
The two equations you need to solve are:
y = 4x .... (1)
x + 30 = (y + 30)/2 .... (2)
Hi are the answers daughter=15 and carla =60.
I sure it must be.
You are correct.Quote:
Originally Posted by anthonye