solve for $\displaystyle x $ $\displaystyle 15xy-8x^2=0 $
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One solution is x = 0. The other depends on y.
There will be two solutions for x: $\displaystyle 15xy-8x^2=0$ $\displaystyle x(15y-8x)=0$ $\displaystyle x=0$ or $\displaystyle 15y-8x=0$ $\displaystyle 15y=8x$ $\displaystyle x=\frac{15y}{8}$ or $\displaystyle x=0$
Originally Posted by Punch solve for $\displaystyle x $ $\displaystyle 15xy-8x^2=0 $ Factor... $\displaystyle x(15y-8x)=0$ $\displaystyle x=0$ $\displaystyle 15y=8x\Rightarrow\ \frac{x}{y}=\frac{15}{8}$ Hence, x=0 or x:y=15:8
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