# Thread: Help With A simple maths problem

1. ## Help With A simple maths problem

Hi,

First off the bat I need to say that I'm so bad at maths I'm not even sure what category this math problem belongs in so apologies if I've posted it in the wrong area.

The Problem:

I have this formula that I use to calculate a decibel level.

db_gain=(x * (8 / 5)) - 90;

When Using this formula db_gain value is not known and x value is known.

How can I switch around? I.E db_gain is known but x is not?

Thanks,

dub

2. Originally Posted by dubbeat
Hi,

First off the bat I need to say that I'm so bad at maths I'm not even sure what category this math problem belongs in so apologies if I've posted it in the wrong area.

The Problem:

I have this formula that I use to calculate a decibel level.

db_gain=(x * (8 / 5)) - 90;

When Using this formula db_gain value is not known and x value is known.

How can I switch around? I.E db_gain is known but x is not?

Thanks,

dub
The formula has db_gain "in terms of x" so that you can calculate db_gain if x is known.

You want x "in terms of db_gain" so that you can calculate x from db_gain.

This requires moving the constants across to db_gain,
either using rules or knowing why..

$\displaystyle \displaystyle\ db_-gain=x\ \frac{8}{5}-90$

$\displaystyle \displaystyle\ db_-gain+90=x\ \frac{8}{5}+90-90=x\ \frac{8}{5}$

$\displaystyle \displaystyle\ (db_-gain+90)\ \frac{5}{8}=x\ \frac{8}{5}\ \frac{5}{8}=x$

3. thanks for that. Showing the steps involved is especially useful