Hi, I need some help step by step with simplifying this please...
$\displaystyle e^x^2 - 4(e^x)^2 + (-3)e^x^2 + (2ee^2^x^-^1) $
You can further factorise out -2, to give:
$\displaystyle -2(e^x^2 + e^2x)$
$\displaystyle 2ee^{2x-1} = 2e.e^{2x}.e^{-1} = \dfrac{2e.e^{2x}}{e}$
e divided by e is 1.
Or you go with combining the powers:
$\displaystyle 2ee^{2x-1} = 2e^{2x - 1 + 1}= 2e^{2x}$