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Math Help - simplify exponential problem...

  1. #1
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    simplify exponential problem...

    Hi, I need some help step by step with simplifying this please...

    e^x^2  - 4(e^x)^2 + (-3)e^x^2 + (2ee^2^x^-^1)
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    Hi, I need some help step by step with simplifying this please...

    e^x^2  - 4(e^x)^2 + (-3)e^x^2 + (2ee^2^x^-^1)
    if this is the expression you meant to post ...

    e^{x^2}  - 4(e^x)^2 + (-3)e^{x^2} + (2e \cdot e^{2x-1})=

    e^{x^2}  - 4e^{2x} - 3e^{x^2} + 2e^{2x}

    finish by combining like terms.
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  3. #3
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    Quote Originally Posted by skeeter View Post
    if this is the expression you meant to post ...

    e^{x^2}  - 4(e^x)^2 + (-3)e^{x^2} + (2e \cdot e^{2x-1})=

    e^{x^2}  - 4e^{2x} - 3e^{x^2} + 2e^{2x}

    finish by combining like terms.
    Would the final answer be this -2e^x^2 -2e^2^x?
    So the -1 exponent disappears at the end because 2e^+1 is multiplying it out?

    Thanks
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  4. #4
    MHF Contributor Unknown008's Avatar
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    You can further factorise out -2, to give:

    -2(e^x^2 + e^2x)

    2ee^{2x-1} = 2e.e^{2x}.e^{-1} = \dfrac{2e.e^{2x}}{e}

    e divided by e is 1.

    Or you go with combining the powers:

    2ee^{2x-1} = 2e^{2x - 1 + 1}= 2e^{2x}
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