[{(x-y)^2-z^2}/{(x+y)^2-z^2}]*[(x+y-z)/(x-y+z)]

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- Oct 6th 2010, 08:16 PMPR98I am having trouble simplifying this. Any suggestions?
[{(x-y)^2-z^2}/{(x+y)^2-z^2}]*[(x+y-z)/(x-y+z)]

- Oct 6th 2010, 08:18 PMharish21
Do you mean:

$\displaystyle \frac{(x-y)^{2}-z^2}{(x+y)^{2}-z^2} \times \frac{(x+y-z)}{(x-y+z)}$ ???

If so, use $\displaystyle {a^2} - {b^2} = (a+b) (a-b)$ to write $\displaystyle (x-y)^{2}-z^2 = (x-y-z)(x-y+z)$.

do the same for the denominator and cancel out like terms! - Oct 6th 2010, 09:34 PMbigwave
you may want to look at this

http://www.wolframalpha.com/input/?i=[{(x-y)^2-z^2}%2F{(x%2By)^2-z^2}]*[(x%2By-z)%2F(x-y%2Bz)]

doesn't look like its going to simplify too much... that is if OP is correct.. - Oct 7th 2010, 05:28 AMPR98That's it!