1. Can the formula be solved for either r or t? Explain. 2. if the formula can be solved for r, what does r=? 2-3rt+t=3t^2-t+r^2t^2-5r^2
Here's a starter for you: (this one is for the variable t)
$\displaystyle 2-3rt+t=3t^2-t+r^2t^2-5r^2$
$\displaystyle 2-3rt+t-3t^2+t-r^2t^2+5r^2=0$
$\displaystyle -3t^2-r^2t^2-3rt+2t+5r^2+2=0$
$\displaystyle t^2(-3-r^2)+t(-3r+2)+5r^2+2=0$
Now can you solve for the variable t?
I think you factorised wrong... maybe you should try again? As I can see from the equation, there are two r^2 parts. So where'd the second part go?
Also it may pay to learn LaTeX so it is easier to understand.
LaTeX Tutorial
oh...so it should instead be $\displaystyle r^2(5+2)$ so then the $\displaystyle (5+2)=7$? so in that case would the $\displaystyle (-3t^2)$ and $\displaystyle (5+2)=7$ be combined into $\displaystyle (-3t^2+7)$? or would they just be separated to create $\displaystyle r=3t^2+-\sqrt(-3t+2t)^2-4(-3t^2)(7)/2(-3t^2)$