Originally Posted by

**SomeRandomPerson** @Skeeter: Thanks a bunch for your help, and for the link. I will look at it.

@Archie: I get your 0 approach now. I'm a little confused about this though:

So x = 1 which is fine with me. But I'm confused as to how to start the equation. I thought you just move the number over and then do the opposite operation, which is why I used addition.

**But you didn't do the opposite operation for the 7x. Let's look at that....**

7x-3=4x

You want to find x. If we subtract 4x from both sides, we will get x on one side only

+7x-3=+4x

+7x-3-4x=+4x-4x

7x-4x-3=0

You can do that more quickly by bringing 4x to the other side and changing it's sign.

7x-3=4x

7x-4x-3=0

so we get 3x-3=0

Alternatively, you can subtract 7x from both sides

7x-3=4x

7x-7x-3=4x-7x

-3=-3x

Basically, my question is how do you start it, and how do you know which operation to use? What order do you put it in? How would I know what order to put it in?

**You simply perform the OPPOSITE OPERATION on the x term you want to move.**

7x-3=4x

+7x-3=0+4x

If you want to bring the x's together, you can subtract 4x from both sides to get no x on the right

or subtract 7x from both sides to get no x on the left.

Alternatively, write 7x as 3x+4x

7x-3=4x

3x+4x-3=4x

4x+(3x-3)=4x+0

3x-3=0

Two values are equal, when you subtract them the answer is 0.

3x=3

3(1)=3 so x=1, or divide both sides by 3.

Multiplying x by 3 gives 3, so perform the opposite operation. Divide both sides by 3 to get x.

3x=3

3x/3=3/3

x(3/3)=3/3

x(1)=1 so x=1

Gah, I never thought such simple questions would cause so many problems with me!