1. ## Completing the square

How would I complete the square with the following?

4x^2-25

I thought of $(4x+\frac{0}{2}^2)-25+\frac{0}{2}^2$ but that doesn't make any sense!

2. Why would you want to complete the square? This is the difference of two squares and will easily factor

$4x^2-25 = (2x)^2 - 5^2$ and the difference of two squares is $a^2-b^2 = (a-b)(a+b)$

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If you want/must to complete the square you have the right idea but the first step is always to make sure the coefficent of $x^2$ is $1$

$4x^2-25 = x^2 - \dfrac{25}{4} = (x+0)^2 - \dfrac{25}{4} = (x+0)^2 - \left(\dfrac{5}{2}\right)^2$

3. need it to work out the minimum point of a graph. Thanks!

4. Ah right, in this case it might be easier to spot that $4x^2 \geq 0$ for all real x.

The mininum will therefore be when $4x^2 = 0$ hence the minimum will be (0,-25)

5. You "complete the square" to get rid of a term of the form "ax", that is x to the 1 power, in a quadratic. In your example, $4x^2- 25$, there is no "x" term- " $4x^2$" is already a perfect square. The minimum value occurs when x= 0 and is -25. Since $4x^2- 25= (2x- 5)(2x+ 5)$ the graph of $y= 4x^2- 25$ is a parabola with vertex at (0, -25), vertical axis, opening upward, and with x-intercepts at (5/2, 0) and (-5/2, 0).