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Thread: exponent question

  1. #1
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    exponent question

    How do I write$\displaystyle (-x^y^2)^4$ without parentheses

    Is it $\displaystyle x^4^y^8$?
    explain please
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    How do I write$\displaystyle (-x^y^2)^4$ without parentheses
    $\displaystyle (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}$
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  3. #3
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    Thanks but how does the y^2 exponent stay the same?
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  4. #4
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    Quote Originally Posted by skeeter View Post
    $\displaystyle (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}$
    Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4
    Last edited by mr fantastic; Oct 4th 2010 at 01:06 AM. Reason: Deleted unnecessary text.
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  5. #5
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    Quote Originally Posted by Wilmer View Post
    Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4
    take another look at the original post ...
    Last edited by mr fantastic; Oct 4th 2010 at 01:06 AM. Reason: Edited quote.
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  6. #6
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    Hes correct, I just don't understand the way $\displaystyle y^2$ is not raised to $\displaystyle y^8$ ?
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  7. #7
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    Quote Originally Posted by wolfhound View Post
    Hes correct, I just don't understand the way $\displaystyle y^2$ is not raised to $\displaystyle y^8$ ?
    the rule is ...

    $\displaystyle (x^a)^b = x^{a \cdot b}$

    so, if $\displaystyle a = y^2$ and $\displaystyle b = 4$ ... what is the result?
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  8. #8
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    um $\displaystyle 4y^2$ ....
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  9. #9
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    Quote Originally Posted by wolfhound View Post
    um $\displaystyle 4y^2$ ....
    bingo
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