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Math Help - exponent question

  1. #1
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    exponent question

    How do I write (-x^y^2)^4 without parentheses

    Is it x^4^y^8?
    explain please
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  2. #2
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    Quote Originally Posted by wolfhound View Post
    How do I write (-x^y^2)^4 without parentheses
    (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}
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  3. #3
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    Thanks but how does the y^2 exponent stay the same?
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  4. #4
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    Quote Originally Posted by skeeter View Post
    (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}
    Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4
    Last edited by mr fantastic; October 4th 2010 at 01:06 AM. Reason: Deleted unnecessary text.
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  5. #5
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    Quote Originally Posted by Wilmer View Post
    Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4
    take another look at the original post ...
    Last edited by mr fantastic; October 4th 2010 at 01:06 AM. Reason: Edited quote.
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  6. #6
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    Hes correct, I just don't understand the way y^2 is not raised to y^8 ?
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  7. #7
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    Quote Originally Posted by wolfhound View Post
    Hes correct, I just don't understand the way y^2 is not raised to y^8 ?
    the rule is ...

    (x^a)^b = x^{a \cdot b}

    so, if a = y^2 and b = 4 ... what is the result?
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  8. #8
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    um 4y^2 ....
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  9. #9
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    Quote Originally Posted by wolfhound View Post
    um 4y^2 ....
    bingo
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