1. exponent question

How do I write$\displaystyle (-x^y^2)^4$ without parentheses

Is it $\displaystyle x^4^y^8$?

2. Originally Posted by wolfhound
How do I write$\displaystyle (-x^y^2)^4$ without parentheses
$\displaystyle (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}$

3. Thanks but how does the y^2 exponent stay the same?

4. Originally Posted by skeeter
$\displaystyle (-x^{y^2})^4 = (-1)^4 \cdot (x^{y^2})^4 = x^{4y^2}$
Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4

5. Originally Posted by Wilmer
Don't think so. We have -x^, not (-x)^ ; like, -2^2 = -4, (-2)^2 = 4
take another look at the original post ...

6. Hes correct, I just don't understand the way $\displaystyle y^2$ is not raised to $\displaystyle y^8$ ?

7. Originally Posted by wolfhound
Hes correct, I just don't understand the way $\displaystyle y^2$ is not raised to $\displaystyle y^8$ ?
the rule is ...

$\displaystyle (x^a)^b = x^{a \cdot b}$

so, if $\displaystyle a = y^2$ and $\displaystyle b = 4$ ... what is the result?

8. um $\displaystyle 4y^2$ ....

9. Originally Posted by wolfhound
um $\displaystyle 4y^2$ ....
bingo