Thread: Find point of intersection between two straight lines

1. Find point of intersection between two straight lines

That's the instruction I have. Sorry for my bad English.

$mx - 4y = m$

$-4x + my = 2m + 4$

I Thought I should get both of the equations to y = ... , So:

$y = \dfrac{mx-m}{4}$

$y = 2 + \dfrac{4+4x}{m}$

And then:

$\dfrac{mx-m}{4} = 2 + \dfrac{4+4x}{m}$

$m(mx-m) = 8m +4(4+4x)$

$m^{2}x - m^{2} -8m-16-16x = 0$

And now I don't know how to continue...

2. You've done very good, correct work so far! Now it's a good time to remember what it is for which you are trying to solve. What is that?

3. "Combine like terms". That is, combine all terms involving "x" on one side of the equation, all terms that do not on the other.