How do i solve these? 1.) -12x=x+26 2.) 3X=2X-10
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in both cases, your aim is to get all the X's on the same side, and everything else on the other side 1) (subtract x from both sides) -12x - x = x-x + 26 -13x = 0 + 26 -13x = 26 (divide by -13) x = -2 You try (2).
Originally Posted by benjixbunn How do i solve these? 1.) -12x = x+26 -12x = x-13x x-13x = x+26 -13x = 26 -13x = -13(-2) x = -2 2.) 3X = 2X-10 3x = 2x+x 2x+x = 2x-10 x = -10 .
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