Alright, this has stumped me.

How can I rearrange:

2x^3 - x - 4 = 0

to be:

x = ROOT(2/x + 1/2) ?

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- Sep 30th 2010, 01:30 PMDrummerdude93Rearranging help?
Alright, this has stumped me.

How can I rearrange:

2x^3 - x - 4 = 0

to be:

x = ROOT(2/x + 1/2) ? - Sep 30th 2010, 01:54 PMArchie Meade
Hi Drummerdude,

$\displaystyle 2x^3-x-4=0$

$\displaystyle 2x^3-x=4$

Factor...

$\displaystyle x\left(2x^2-1\right)=4$

$\displaystyle 2x^2-1=\frac{4}{x}$

$\displaystyle 2x^2=\frac{4}{x}+1$

$\displaystyle x^2=\frac{2}{x}+\frac{1}{2}$

Finally, take the square root. - Sep 30th 2010, 01:59 PMskeeter