the function f(x) is such that, f(x) + f(1-x) = k where k is a constant, then , prove that SIGMA(r=1,m)f(r/m+1) = mk/2
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Originally Posted by ice_syncer the function f(x) is such that, f(x) + f(1-x) = k where k is a constant, then , prove that SIGMA(r=1,m)f(r/m+1) = mk/2 Is the function or
Also, since there is no "k" on the left, the right cannot be "mk/2".
works. Write out the sum in two ways, and , add and divide by 2.
it is, r/(m+1)
Yes, r/(m+1) gives the required result, (r/m)+1 doesn't.
so? give the proof
so alternatively, Now add the two expressions for together and divide by two.
Just noticed I missed an on the last line .
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