Ok, so I have a question involving a Polynomial and finding its roots.

Given $\displaystyle x^3-4x^2 + 2x+1=0$

A. How many possible positive roots are there?

(Answer: 1)

B. How many possible negative roots are there?

(Answer:1)

C. What are the possible rational roots?

(Answer:$\displaystyle \frac{1}{1},-\frac{1}{1} $

D. Using synthetic substitution, which of the possible rational roots is actually a root of the equation?

(Answer:I'm not sure on how to show synthetic division/substitution using [tex] tags, but my answer is that 1 is the actual real root of the equation.)

E. Use the quadratic formula to find the irrational roots of the resultant depressed equation.

(Answer: I'm a little fuzzy here.....the depressed equation I got was: $\displaystyle x^2-3x-1=0$. My question is, did I get the correct equation?

If I did then I am certain that I can do the rest, it is just the quadratic equation--one of the few things I actually understand.)

Thank you.