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Thread: Exponential equations?

  1. September 28th 2010, 01:37 AM #1
    Kaloda
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    Question Exponential equations?

    Solve for x in the inequality 5^x> 25^2^x.
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  2. September 28th 2010, 01:46 AM #2
    CaptainBlack
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    Quote Originally Posted by Kaloda View Post
    Solve for x in the inequality 5^x> 25^2^x.
    Take logs:

    x\ln(5)>2x \ln(25)=2x \ln(5^2)=4x \ln(5)

    CB
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  3. September 28th 2010, 01:49 AM #3
    Prove It
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    An easier way

    5^x > 25^{2x}

    5^x > (5^2)^{2x}

    5^x > 5^{4x}

    x > 4x

    0 > 3x

    0 > x.
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