Exponential equations?

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September 28th 2010, 01:37 AM
Kaloda

Exponential equations?

Solve for $x$ in the inequality $5^x> 25^2^x$ .
September 28th 2010, 01:46 AM
CaptainBlack

Quote:

Originally Posted by Kaloda

Solve for $x$ in the inequality $5^x> 25^2^x$ .

Take logs:

$x\ln(5)>2x \ln(25)=2x \ln(5^2)=4x \ln(5)$

CB
September 28th 2010, 01:49 AM
Prove It

An easier way

$5^x > 25^{2x}$

$5^x > (5^2)^{2x}$

$5^x > 5^{4x}$

$x > 4x$

$0 > 3x$

$0 > x$ .

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