# Perimeter of the design

• Sep 27th 2010, 10:28 PM
alanpaul
Perimeter of the design
drawing and measurement of a rectangle and square are shown in attached file.

• Sep 27th 2010, 11:09 PM
RHandford
Hi

Well I make it 2(11+6*2+5)+6+6cm

Can you see where the numbers come from?
• Sep 28th 2010, 06:00 AM
Wilmer
Hmmm...I make it 2(11 + 6 + 5 + 12) = 68
(But I've only had one coffee so far...)
• Sep 28th 2010, 09:56 PM
alanpaul
Please can you explain how do u arrive the figure 68 . Why did apply the formula 2(11+6*2+5)+6+6cm
If you can expalin the mathod it would be very appreciate.
• Sep 28th 2010, 10:28 PM
RHandford
Quote:

Originally Posted by alanpaul
Please can you explain how do u arrive the figure 68 . Why did apply the formula 2(11+6*2+5)+6+6cm
If you can expalin the mathod it would be very appreciate.

Attachment 19117

So

2(11+6*2+5)+6+6 cm = 2(A+B*2+D)+C+C cm (Please see attached edited diagram)

2(A+B*2+D) - This part deals with the rectangles at the top and bottom. It is multiplied by two as they are the same.
+C+C cm - This part deals with the square in the middle.

As the image is equal round the center axis you could change it to:

2(11+6*2+11) cm which should give you the same answer, but as I have not had my coffee yet I would not guarantee it! (Happy)
• Sep 28th 2010, 10:46 PM
RHandford
Hi

I have just noticed you dont really need to do all the above.
As the shape in the middle is a square you just need:
4(11+6) or 4(A+B)
because the square in the middle gets canceled out.

Hope this helps (Clapping)