write f(x) = (2x^3 -7)^5 as 2 simpler functions
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Originally Posted by yess write f(x) = (2x^3 -7)^5 as 2 simpler functions Does this mean rewrite $\displaystyle f(x)$ as: $\displaystyle f(x)=g(h(x))$ where $\displaystyle g$ and $\displaystyle h$ are in some sense simpler? CB
You're question is kind of vague. Are you looking for something like this? $\displaystyle f(x)=g(h(x))$
Originally Posted by CaptainBlack Does this mean rewrite $\displaystyle f(x)$ as: $\displaystyle f(x)=g(h(x))$ where $\displaystyle g$ and $\displaystyle h$ are in some sense simpler? CB yes sorry thats what i meant!
Originally Posted by yess yes sorry thats what i meant! Originally Posted by yess write f(x) = (2x^3 -7)^5 as 2 simpler functions Originally Posted by CaptainBlack Does this mean rewrite $\displaystyle f(x)$ as: $\displaystyle f(x)=g(h(x))$ where $\displaystyle g$ and $\displaystyle h$ are in some sense simpler? CB ' How about $\displaystyle h(x)=x^3$, then $\displaystyle g(x)=(2x-7)^5$ or maybe something simpler yet? CB
Last edited by CaptainBlack; Sep 28th 2010 at 02:23 PM. Reason: correct typo
Shouldn't it be: $\displaystyle f(x)=g(h(x))$ Where $\displaystyle g(x)=x^{5}$ and $\displaystyle h(x)=(2x^{3}-7)$
Originally Posted by downthesun01 Shouldn't it be: $\displaystyle f(x)=g(h(x))$ Where $\displaystyle g(x)=x^{5}$ and $\displaystyle h(x)=(2x^{3}-7)$ There is no unique solution. CB
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