Rewrite this function...

**yess** · September 27th 2010, 09:43 PM

write f(x) = (2x^3 -7)^5 as 2 simpler functions

**CaptainBlack** · September 28th 2010, 01:51 AM

Originally Posted by yess

write f(x) = (2x^3 -7)^5 as 2 simpler functions

Does this mean rewrite $f(x)$ as:

$f(x)=g(h(x))$

where $g$ and $h$ are in some sense simpler?

CB

**downthesun01** · September 28th 2010, 01:51 AM

You're question is kind of vague. Are you looking for something like this?

$f(x)=g(h(x))$

**yess** · September 28th 2010, 06:49 AM

Originally Posted by CaptainBlack

Does this mean rewrite $f(x)$ as:

$f(x)=g(h(x))$

where $g$ and $h$ are in some sense simpler?

CB

yes sorry thats what i meant!

**CaptainBlack** · September 28th 2010, 08:31 AM

Originally Posted by yess

yes sorry thats what i meant!

Originally Posted by yess

write f(x) = (2x^3 -7)^5 as 2 simpler functions

Originally Posted by CaptainBlack

Does this mean rewrite $f(x)$ as:

$f(x)=g(h(x))$

where $g$ and $h$ are in some sense simpler?

CB

'

How about $h(x)=x^3$ , then $g(x)=(2x-7)^5$ or maybe something simpler yet?

CB

**downthesun01** · September 28th 2010, 01:03 PM

Shouldn't it be:

$f(x)=g(h(x))$

Where

$g(x)=x^{5}$ and $h(x)=(2x^{3}-7)$

**CaptainBlack** · September 28th 2010, 02:24 PM

Originally Posted by downthesun01

Shouldn't it be:

$f(x)=g(h(x))$

Where

$g(x)=x^{5}$ and $h(x)=(2x^{3}-7)$

There is no unique solution.

CB

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