# Rewrite this function...

• Sep 27th 2010, 09:43 PM
yess
Rewrite this function...
write f(x) = (2x^3 -7)^5 as 2 simpler functions
• Sep 28th 2010, 01:51 AM
CaptainBlack
Quote:

Originally Posted by yess
write f(x) = (2x^3 -7)^5 as 2 simpler functions

Does this mean rewrite \$\displaystyle f(x)\$ as:

\$\displaystyle f(x)=g(h(x))\$

where \$\displaystyle g\$ and \$\displaystyle h\$ are in some sense simpler?

CB
• Sep 28th 2010, 01:51 AM
downthesun01
You're question is kind of vague. Are you looking for something like this?

\$\displaystyle f(x)=g(h(x))\$
• Sep 28th 2010, 06:49 AM
yess
Quote:

Originally Posted by CaptainBlack
Does this mean rewrite \$\displaystyle f(x)\$ as:

\$\displaystyle f(x)=g(h(x))\$

where \$\displaystyle g\$ and \$\displaystyle h\$ are in some sense simpler?

CB

yes sorry thats what i meant!
• Sep 28th 2010, 08:31 AM
CaptainBlack
Quote:

Originally Posted by yess
yes sorry thats what i meant!

Quote:

Originally Posted by yess
write f(x) = (2x^3 -7)^5 as 2 simpler functions

Quote:

Originally Posted by CaptainBlack
Does this mean rewrite \$\displaystyle f(x)\$ as:

\$\displaystyle f(x)=g(h(x))\$

where \$\displaystyle g\$ and \$\displaystyle h\$ are in some sense simpler?

CB

'

How about \$\displaystyle h(x)=x^3\$, then \$\displaystyle g(x)=(2x-7)^5\$ or maybe something simpler yet?

CB
• Sep 28th 2010, 01:03 PM
downthesun01
Shouldn't it be:

\$\displaystyle f(x)=g(h(x))\$

Where

\$\displaystyle g(x)=x^{5}\$ and \$\displaystyle h(x)=(2x^{3}-7)\$
• Sep 28th 2010, 02:24 PM
CaptainBlack
Quote:

Originally Posted by downthesun01
Shouldn't it be:

\$\displaystyle f(x)=g(h(x))\$

Where

\$\displaystyle g(x)=x^{5}\$ and \$\displaystyle h(x)=(2x^{3}-7)\$

There is no unique solution.

CB