pretty easy question.. can't get answer in the back of the book though. x2 + 6y -y2 -9 my answer (x-3)(x+3) + y(6-y) back of book (x+y-3)(x-y+3)
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$\displaystyle x^2 + 6y -y^2 -9$ $\displaystyle x^2 -y^2 + 6y-9$ $\displaystyle x^2 -(y^2 - 6y+9)$ $\displaystyle x^2 -(y- 3)^2$ Using the difference of two squares rule. $\displaystyle (x -(y- 3))(x +(y- 3))$ $\displaystyle (x -y+ 3)(x +y- 3)$
lol cant believe i missed that, thanks.
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