Hi, i am struggling with factorising the quadratic equations. I have got to grips with basic factorisation. any help?

1. solve the following quadratic equations by factorisation:

a)

(x+6)(x-3)=22

......

i have tried this one and came out with this answer:

x(x-3)+6(x-3)=22

x^2-3x+6x-18=22

x^2+3x-22-16=0

x^2+3x-38

(x+19)(x-2)

Is this correct?

b) 20x=4+3/x

c) 4t(3t-2)=3-8t

2.

a) x^2=7x+4

b) (3x+4)(x-1)=1

c) 1/2x-7=x/x-1