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Math Help - Function Notation

  1. #1
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    Function Notation

    a bit stuck here...


    question:


    compute \frac{4g(-5)+[g(2)]^{2}}{-2g(3)}


    also:
    how would i solve f[k(-8)] , when i am given other variables for f and k to solve for other functions? i may need to explain that question better, but need to get away from the computer quick


    explanation of how to solve it would be great.... not looking for the answer.
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  2. #2
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    Quote Originally Posted by pychon View Post
    a bit stuck here...


    question:


    compute \frac{4g(-5)+[g(2)]^{2}}{-2g(3)}

    would help to know how g(x) is defined ...


    also:
    how would i solve f[k(-8)] , when i am given other variables for f and k to solve for other functions? i may need to explain that question better, but need to get away from the computer quick

    ditto ... f(x) = ??? and k(x) = ???
    ...
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  3. #3
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    first questions variables:
    Code:
    x| -5 |-4|-3|-2|-1| 0|  1| 2| 3
    ---------------------------------
    y| 12 | 9| 4| 0|-1|-3| -5|-6|-8
    i suspect i should take and write as
    \frac{4g(-5)+[g(2)]^{2}}{-2g(3)}


    \frac{4(-3)(-5)+[-6(2)]^{2}}{-2(0)(3)}


    second question variables are:

    f(x) = -4x+3

    k(x) = \sqrt[3]{x}


    so, f[k(-8)] would be f(x) = -4(-8)+3 or is it -4(\sqrt[3]{2})+3


    my college math book doesn't explain a bleeping thing how to do what. so if anyone knows of any literature, or preferably videos, on explicit functions and relationship problems wth problems like these that would be great... even domain and range.
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  4. #4
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    start here ...

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  5. #5
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    Quote Originally Posted by skeeter View Post
    start here ...


    actually, was just watching those... but doesn't explain similar problems i have posted (yet) and his domain and range -infinity?!- come on use math terminology... x \leq n or x \geq  n
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  6. #6
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    first questions variables:
    Code:
    x| -5 |-4|-3|-2|-1| 0|  1| 2| 3
    ---------------------------------
    y| 12 | 9| 4| 0|-1|-3| -5|-6|-8
    if the table represents g(x) , then g(-5) = 12 , g(2) = -6 , and g(3) = -8

    \displaystyle \frac{4g(-5)+[g(2)]^{2}}{-2g(3)}

    should be

    \displaystyle \frac{4(12)+(-6)^{2}}{-2(-8)} = \frac{48 + 36}{16}


    second question variables are:

    f(x) = -4x+3

    k(x) = \sqrt[3]{x}

    f[k(-8)] = f[\sqrt[3]{-8}] = f(-2) = -4(-2) + 3 = 11
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