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Math Help - Problem of Mixture

  1. #1
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    Problem of Mixture

    Coffee A normally costs $ 100 per lb. It is mixed with coffee B, which normally costs $ 70 per lb, to form a mixture that costs $ 88 per lb. If there are 10 lbs of the mix, how many pounds of coffee A is used in the mixture?


    Actually I don't get this problem properly.

    What I got so far,
    Coffee A costs $ 100 per lb, coffee B costs $ 70 per lb. Their mixture in certain ratio costs $ 88 per lb. Then how I count the ratio from this?
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  2. #2
    Member Traveller's Avatar
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    You add x units of A and y units of B, and you want to find \frac{x}{y}.

    Try to get this equation somehow and solve it for \frac{x}{y}:

    100x + 70y = 88(x + y)
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  3. #3
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    Then I got, x:y = 3:2

    Therefore, the amount of coffee A in the mixture is 10 x 3/5 = 6 lbs.


    Is that the right way to do?
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  4. #4
    Member Traveller's Avatar
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    Perfect.
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