Hello everyone. I have an algebra question:

Given thatyvaries directly as the cube ofx, find the percentage decrease inyifxis halved.

Since $\displaystyle y$ is in direct proportion with $\displaystyle x^3$,

let $\displaystyle y=kx^3$, where k is a constant.

If x is halved, it would be $\displaystyle \dfrac{x^3}{2}$.

But it doesn't solve the problem.

I wonder how the percentage can be calculated when there are no values for $\displaystyle x$ and $\displaystyle y$...